Lista de todas as colunas de índice e índice no database do SQL Server

Como faço para obter uma lista de todas as colunas de índice e índice no SQL Server 2005+? O mais próximo que consegui é:

select s.name, t.name, i.name, c.name from sys.tables t inner join sys.schemas s on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id where i.index_id > 0 and i.type in (1, 2) -- clustered & nonclustered only and i.is_primary_key = 0 -- do not include PK indexes and i.is_unique_constraint = 0 -- do not include UQ and i.is_disabled = 0 and i.is_hypothetical = 0 and ic.key_ordinal > 0 order by ic.key_ordinal 

O que não é exatamente o que eu quero.
O que eu quero é listar todos os índices definidos pelo usuário (o que significa que nenhum índice suporta restrições exclusivas e chaves primárias ) com todas as colunas (ordenadas por como elas aparecem na definição do índice) mais o máximo de metadados possíveis.

Existem duas visualizações de catálogo “sys” que você pode consultar:

 select * from sys.indexes 

 select * from sys.index_columns 

Esses lhe darão praticamente qualquer informação que você possa querer sobre índices e suas colunas.

EDIT: esta consulta está ficando muito perto do que você está procurando:

 SELECT TableName = t.name, IndexName = ind.name, IndexId = ind.index_id, ColumnId = ic.index_column_id, ColumnName = col.name, ind.*, ic.*, col.* FROM sys.indexes ind INNER JOIN sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id INNER JOIN sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id INNER JOIN sys.tables t ON ind.object_id = t.object_id WHERE ind.is_primary_key = 0 AND ind.is_unique = 0 AND ind.is_unique_constraint = 0 AND t.is_ms_shipped = 0 ORDER BY t.name, ind.name, ind.index_id, ic.index_column_id; 

Você pode usar o sp_helpindex para visualizar todos os índices de uma tabela.

 EXEC sys.sp_helpindex @objname = N'User' -- nvarchar(77) 

E para todos os índices, você pode percorrer sys.objects para obter todos os índices para cada tabela.

Nenhum dos acima fez o trabalho para mim, mas isso faz:

 -- KDF9's concise index list for SQL Server 2005+ (see below for 2000) -- includes schemas and primary keys, in easy to read format -- with unique, clustered, and all ascending/descendings in a single column -- Needs simple manual add or delete to change maximum number of key columns -- but is easy to understand and modify, with no UDFs or complex logic -- SELECT schema_name(schema_id) as SchemaName, OBJECT_NAME(si.object_id) as TableName, si.name as IndexName, (CASE is_primary_key WHEN 1 THEN 'PK' ELSE '' END) as PK, (CASE is_unique WHEN 1 THEN '1' ELSE '0' END)+' '+ (CASE si.type WHEN 1 THEN 'C' WHEN 3 THEN 'X' ELSE 'B' END)+' '+ -- B=basic, C=Clustered, X=XML (CASE INDEXKEY_PROPERTY(si.object_id,index_id,1,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,2,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,3,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,4,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,5,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,6,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ '' as 'Type', INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,1) as Key1, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,2) as Key2, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,3) as Key3, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,4) as Key4, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,5) as Key5, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,6) as Key6 FROM sys.indexes as si LEFT JOIN sys.objects as so on so.object_id=si.object_id WHERE index_id>0 -- omit the default heap and OBJECTPROPERTY(si.object_id,'IsMsShipped')=0 -- omit system tables and not (schema_name(schema_id)='dbo' and OBJECT_NAME(si.object_id)='sysdiagrams') -- omit sysdiagrams ORDER BY SchemaName,TableName,IndexName ------------------------------------------------------------------- -- or to generate creation scripts put a simple wrapper around that SELECT SchemaName, TableName, IndexName, (CASE pk WHEN 'PK' THEN 'ALTER '+ 'TABLE '+SchemaName+'.'+TableName+' ADD CONSTRAINT '+IndexName+' PRIMARY KEY'+ (CASE substring(Type,3,1) WHEN 'C' THEN ' CLUSTERED' ELSE '' END) ELSE 'CREATE '+ (CASE substring(Type,1,1) WHEN '1' THEN 'UNIQUE ' ELSE '' END)+ (CASE substring(Type,3,1) WHEN 'C' THEN 'CLUSTERED ' ELSE '' END)+ 'INDEX '+IndexName+' ON '+SchemaName+'.'+TableName END)+ ' ('+ (CASE WHEN Key1 is null THEN '' ELSE Key1+(CASE substring(Type,4+1,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key2 is null THEN '' ELSE ', '+Key2+(CASE substring(Type,4+2,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key3 is null THEN '' ELSE ', '+Key3+(CASE substring(Type,4+3,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key4 is null THEN '' ELSE ', '+Key4+(CASE substring(Type,4+4,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key5 is null THEN '' ELSE ', '+Key5+(CASE substring(Type,4+5,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key6 is null THEN '' ELSE ', '+Key6+(CASE substring(Type,4+6,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ ')' as CreateIndex FROM ( ... ...listing SQL same as above minus the ORDER BY... ... ) as indexes ORDER BY SchemaName,TableName,IndexName ---------------------------------------------------------- -- For SQL Server 2000 the following should work -- change table names to sysindexes and sysobjects (no dots) -- change object_id => id, index_id => indid, -- change is_primary_key => (select count(constid) from sysconstraints as sc where sc.id=si.id and sc.status&15=1) -- change is_unique => INDEXPROPERTY(si.id,si.name,'IsUnique') -- change si.type => INDEXPROPERTY(si.id,si.name,'IsClustered') -- remove all references to schemas including schema name qualifiers, and the XML type -- add select where indid<255 and si.status&64=0 (to omit the text/image index and autostats) 

Se seus nomes incluem espaços, adicione colchetes ao redor deles nos scripts de criação.

Quando a última coluna Key é toda nula, você sabe que nenhuma está faltando.

Filtrar as chaves primárias, etc, como na solicitação original, é trivial.

NOTA: Tome cuidado com essa solução, pois ela não distingue colunas indexadas e incluídas.

–Curto e grosso:

 SELECT OBJECT_SCHEMA_NAME(T.[object_id],DB_ID()) AS [Schema], T.[name] AS [table_name], I.[name] AS [index_name], AC.[name] AS [column_name], I.[type_desc], I.[is_unique], I.[data_space_id], I.[ignore_dup_key], I.[is_primary_key], I.[is_unique_constraint], I.[fill_factor], I.[is_padded], I.[is_disabled], I.[is_hypothetical], I.[allow_row_locks], I.[allow_page_locks], IC.[is_descending_key], IC.[is_included_column] FROM sys.[tables] AS T INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id] INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id] INNER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id] WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP' ORDER BY T.[name], I.[index_id], IC.[key_ordinal] 

Ei pessoal, eu não passei, mas consegui o que queria na consulta postada pelo autor original.

Eu usei (sem condições / filtros) para minha exigência, mas deu resultados incorretos

O principal problema foi os resultados obter produto cruzado sem condição de associação no index_id

 SELECT S.NAME SCHEMA_NAME,T.NAME TABLE_NAME,I.NAME INDEX_NAME,C.NAME COLUMN_NAME FROM SYS.TABLES T INNER JOIN SYS.SCHEMAS S ON T.SCHEMA_ID = S.SCHEMA_ID INNER JOIN SYS.INDEXES I ON I.OBJECT_ID = T.OBJECT_ID INNER JOIN SYS.INDEX_COLUMNS IC ON IC.OBJECT_ID = T.OBJECT_ID INNER JOIN SYS.COLUMNS C ON C.OBJECT_ID = T.OBJECT_ID **AND IC.INDEX_ID = I.INDEX_ID** AND IC.COLUMN_ID = C.COLUMN_ID WHERE 1=1 ORDER BY I.NAME,I.INDEX_ID,IC.KEY_ORDINAL 

A seguir, dá o que é semelhante como sp_helpindex tablename

 select T.name as TableName, I.name as IndexName, AC.Name as ColumnName, I.type_desc as IndexType from sys.tables as T inner join sys.indexes as I on T.[object_id] = I.[object_id] inner join sys.index_columns as IC on IC.[object_id] = I.[object_id] and IC.[index_id] = I.[index_id] inner join sys.all_columns as AC on IC.[object_id] = AC.[object_id] and IC.[column_id] = AC.[column_id] order by T.name, I.name 

Eu precisei obter índices específicos, suas colunas de índice e suas colunas incluídas também. Aqui está a consulta que usei:

 SELECT INX.[name] AS [Index Name] ,TBL.[name] AS [Table Name] ,DS1.[IndexColumnsNames] ,DS2.[IncludedColumnsNames] FROM [sys].[indexes] INX INNER JOIN [sys].[tables] TBL ON INX.[object_id] = TBL.[object_id] CROSS APPLY ( SELECT STUFF ( ( SELECT ' [' + CLS.[name] + ']' FROM [sys].[index_columns] INXCLS INNER JOIN [sys].[columns] CLS ON INXCLS.[object_id] = CLS.[object_id] AND INXCLS.[column_id] = CLS.[column_id] WHERE INX.[object_id] = INXCLS.[object_id] AND INX.[index_id] = INXCLS.[index_id] AND INXCLS.[is_included_column] = 0 FOR XML PATH('') ) ,1 ,1 ,'' ) ) DS1 ([IndexColumnsNames]) CROSS APPLY ( SELECT STUFF ( ( SELECT ' [' + CLS.[name] + ']' FROM [sys].[index_columns] INXCLS INNER JOIN [sys].[columns] CLS ON INXCLS.[object_id] = CLS.[object_id] AND INXCLS.[column_id] = CLS.[column_id] WHERE INX.[object_id] = INXCLS.[object_id] AND INX.[index_id] = INXCLS.[index_id] AND INXCLS.[is_included_column] = 1 FOR XML PATH('') ) ,1 ,1 ,'' ) ) DS2 ([IncludedColumnsNames]) 

isso vai funcionar:

 DECLARE @IndexInfo TABLE (index_name varchar(250) ,index_description varchar(250) ,index_keys varchar(250) ) INSERT INTO @IndexInfo exec sp_msforeachtable 'sp_helpindex ''?''' select * from @IndexInfo 

isso não retorna o nome da tabela e você receberá avisos para todas as tabelas sem um índice, se isso for um problema, você pode criar um loop sobre as tabelas que possuem índices como este:

 DECLARE @IndexInfoTemp TABLE (index_name varchar(250) ,index_description varchar(250) ,index_keys varchar(250) ) DECLARE @IndexInfo TABLE (table_name sysname ,index_name varchar(250) ,index_description varchar(250) ,index_keys varchar(250) ) DECLARE @Tables Table (RowID int not null identity(1,1) ,TableName sysname ) DECLARE @MaxRow int DECLARE @CurrentRow int DECLARE @CurrentTable sysname INSERT INTO @Tables SELECT DISTINCT t.name FROM sys.indexes i INNER JOIN sys.tables t ON i.object_id = t.object_id WHERE i.Name IS NOT NULL SELECT @MaxRow=@@ROWCOUNT,@CurrentRow=1 WHILE @CurrentRow< =@MaxRow BEGIN SELECT @CurrentTable=TableName FROM @Tables WHERE RowID=@CurrentRow INSERT INTO @IndexInfoTemp exec sp_helpindex @CurrentTable INSERT INTO @IndexInfo (table_name , index_name , index_description , index_keys) SELECT @CurrentTable , index_name , index_description , index_keys FROM @IndexInfoTemp DELETE FROM @IndexInfoTemp SET @CurrentRow=@CurrentRow+1 END --WHILE SELECT * from @IndexInfo 

EDITAR
se você quiser, você pode filtrar os dados, aqui estão alguns exemplos (estes funcionam para qualquer um dos methods):

 SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%primary key%' SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%nonclustered%' AND index_description LIKE '%clustered%' SELECT * FROM @IndexInfo WHERE index_description LIKE '%unique%' 
 with connect(schema_name,table_name,index_name,index_column_id,column_name) as ( select s.name schema_name, t.name table_name, i.name index_name, index_column_id, cast(c.name as varchar(max)) column_name from sys.tables t inner join sys.schemas s on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id where index_column_id=1 union all select s.name schema_name, t.name table_name, i.name index_name, ic.index_column_id, cast(connect.column_name + ',' + c.name as varchar(max)) column_name from sys.tables t inner join sys.schemas s on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id join connect on connect.index_column_id+1 = ic.index_column_id and connect.schema_name = s.name and connect.table_name = t.name and connect.index_name = i.name) select connect.schema_name,connect.table_name,connect.index_name,connect.column_name from connect join (select schema_name,table_name,index_name,MAX(index_column_id) index_column_id from connect group by schema_name,table_name,index_name) mx on connect.schema_name = mx.schema_name and connect.table_name = mx.table_name and connect.index_name = mx.index_name and connect.index_column_id = mx.index_column_id order by 1,2,3 

O seguinte funciona no SQL Server 2014/2016, bem como em qualquer Banco de Dados SQL do Microsoft Azure.

Produz um conjunto abrangente de resultados que é facilmente exportável para o Notepad / Excel para fatiar e cortar e inclui

  1. Nome da mesa
  2. Nome do índice
  3. Descrição do índice
  4. Colunas Indexadas – Em ordem
  5. Colunas incluídas – em ordem
  SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name' ,+ i.NAME AS 'index_name' ,LOWER(i.type_desc) + CASE WHEN i.is_unique = 1 THEN ', unique' ELSE '' END + CASE WHEN i.is_primary_key = 1 THEN ', primary key' ELSE '' END AS 'index_description' ,STUFF(( SELECT ', [' + sc.NAME + ']' AS "text()" FROM syscolumns AS sc INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id AND ic.column_id = sc.colid WHERE sc.id = so.object_id AND ic.index_id = i1.indid AND ic.is_included_column = 0 ORDER BY key_ordinal FOR XML PATH('') ), 1, 2, '') AS 'indexed_columns' ,STUFF(( SELECT ', [' + sc.NAME + ']' AS "text()" FROM syscolumns AS sc INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id AND ic.column_id = sc.colid WHERE sc.id = so.object_id AND ic.index_id = i1.indid AND ic.is_included_column = 1 FOR XML PATH('') ), 1, 2, '') AS 'included_columns' FROM sysindexes AS i1 INNER JOIN sys.indexes AS i ON i.object_id = i1.id AND i.index_id = i1.indid INNER JOIN sysobjects AS o ON o.id = i1.id INNER JOIN sys.objects AS so ON so.object_id = o.id AND is_ms_shipped = 0 INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id WHERE so.type = 'U' AND i1.indid < 255 AND i1.STATUS & 64 = 0 --index with duplicates AND i1.STATUS & 8388608 = 0 --auto created index AND i1.STATUS & 16777216 = 0 --stats no recompute AND i.type_desc <> 'heap' AND so.NAME <> 'sysdiagrams' ORDER BY table_name ,index_name; 

Esta é uma maneira de fazer o backup nos índices. Você pode usar SHOWCONTIG para avaliar a fragmentação. Ele listará todos os índices do database ou da tabela, junto com as statistics. Gostaria de advertir que em um database grande, pode ser de longa duração. Para mim, um dos benefícios dessa abordagem é que você não precisa ser um administrador para usá-la.

– Mostrar informações de fragmentação em todos os índices em um database

 SET NOCOUNT ON USE pubs DBCC SHOWCONTIG WITH ALL_INDEXES GO 

… DESLIGAR NOCOUNT quando estiver pronto

– Mostrar informações de fragmentação em todos os índices em uma tabela

 SET NOCOUNT ON USE pubs DBCC SHOWCONTIG (authors) WITH ALL_INDEXES GO 

– Mostrar informações de fragmentação em um índice específico

 SET NOCOUNT ON USE pubs DBCC SHOWCONTIG (authors,aunmind) GO 

Posso arriscar outra resposta a essa pergunta saturada?

Esta é uma reformulação liberal da resposta do @marc_s, misturada com algumas coisas da @Tim Ford, com o objective de ter um conjunto de resultados mais simples e mais limpo e exibição final e pedidos para a minha necessidade atual.

 SELECT OBJECT_SCHEMA_NAME(t.[object_id],DB_ID()) AS [Schema], t.[name] AS [TableName], ind.[name] AS [IndexName], col.[name] AS [ColumnName], ic.column_id AS [ColumnId], ind.[type_desc] AS [IndexTypeDesc], col.is_identity AS [IsIdentity], ind.[is_unique] AS [IsUnique], ind.[is_primary_key] AS [IsPrimaryKey], ic.[is_descending_key] AS [IsDescendingKey], ic.[is_included_column] AS [IsIncludedColumn] FROM sys.indexes ind INNER JOIN sys.index_columns ic ON ind.object_id = ic.object_id AND ind.index_id = ic.index_id INNER JOIN sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id INNER JOIN sys.tables t ON ind.object_id = t.object_id WHERE t.is_ms_shipped = 0 --ind.is_primary_key = 1 -- include or not pks, etc --AND ind.is_unique = 0 --AND ind.is_unique_constraint = 0 ORDER BY [Schema], TableName, IndexName, [ColumnId], ColumnName 

com base no código de Tim Ford, esta é a resposta certa:

  select tab.[name] as [table_name], idx.[name] as [index_name], allc.[name] as [column_name], idx.[type_desc], idx.[is_unique], idx.[data_space_id], idx.[ignore_dup_key], idx.[is_primary_key], idx.[is_unique_constraint], idx.[fill_factor], idx.[is_padded], idx.[is_disabled], idx.[is_hypothetical], idx.[allow_row_locks], idx.[allow_page_locks], idxc.[is_descending_key], idxc.[is_included_column], idxc.[index_column_id] from sys.[tables] as tab inner join sys.[indexes] idx on tab.[object_id] = idx.[object_id] inner join sys.[index_columns] idxc on idx.[object_id] = idxc.[object_id] and idx.[index_id] = idxc.[index_id] inner join sys.[all_columns] allc on tab.[object_id] = allc.[object_id] and idxc.[column_id] = allc.[column_id] where tab.[name] Like '%table_name%' and idx.[name] Like '%index_name%' order by tab.[name], idx.[index_id], idxc.[index_column_id] 

Eu criei este, que está me dando a visão exata que eu preciso. O que ajuda é que você obtenha uma linha por índice em que as colunas do índice são agregadas.

 select o.name as ObjectName, i.name as IndexName, i.is_primary_key as [PrimaryKey], SUBSTRING(i.[type_desc],0,6) as IndexType, i.is_unique as [Unique], Columns.[Normal] as IndexColumns, Columns.[Included] as IncludedColumns from sys.indexes i join sys.objects o on i.object_id = o.object_id cross apply ( select substring ( ( select ', ' + co.[name] from sys.index_columns ic join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 0 order by ic.key_ordinal for xml path('') ) , 3 , 10000 ) as [Normal] , substring ( ( select ', ' + co.[name] from sys.index_columns ic join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 1 order by ic.key_ordinal for xml path('') ) , 3 , 10000 ) as [Included] ) Columns where o.[type] = 'U' --USER_TABLE order by o.[name], i.[name], i.is_primary_key desc 

Com base na resposta aceita e em outras duas perguntas 1 , 2 , montei a seguinte consulta:

 SELECT sys.indexes.name AS IndexName, sys.tables.name AS TableName, REPLACE(( SELECT sys.columns.name + CASE WHEN is_descending_key = 1 THEN ' DESC' ELSE '' END AS [data()] FROM sys.index_columns INNER JOIN sys.columns ON sys.index_columns.object_id = sys.columns.object_id AND sys.index_columns.column_id = sys.columns.column_id WHERE sys.index_columns.object_id = sys.indexes.object_id AND sys.index_columns.index_id = sys.indexes.index_id AND sys.index_columns.is_included_column = 0 ORDER BY sys.index_columns.key_ordinal FOR XML PATH('') ), ' ', ', ') AS KeyColumns, REPLACE(( SELECT sys.columns.name AS [data()] FROM sys.index_columns INNER JOIN sys.columns ON sys.index_columns.object_id = sys.columns.object_id AND sys.index_columns.column_id = sys.columns.column_id WHERE sys.index_columns.object_id = sys.indexes.object_id AND sys.index_columns.index_id = sys.indexes.index_id AND sys.index_columns.is_included_column = 1 ORDER BY sys.index_columns.index_column_id FOR XML PATH('') ), ' ', ', ') AS IncludedColumns, sys.dm_db_index_usage_stats.user_updates, sys.dm_db_index_usage_stats.user_seeks, sys.dm_db_index_usage_stats.user_scans, sys.dm_db_index_usage_stats.user_lookups, sys.dm_db_index_usage_stats.user_seeks + sys.dm_db_index_usage_stats.user_scans + sys.dm_db_index_usage_stats.user_lookups AS total_usage FROM sys.indexes LEFT JOIN sys.tables ON sys.indexes.object_id = sys.tables.object_id LEFT JOIN sys.dm_db_index_usage_stats ON sys.indexes.object_id = sys.dm_db_index_usage_stats.object_id AND sys.indexes.index_id = sys.dm_db_index_usage_stats.index_id WHERE sys.indexes.type <> 0 AND sys.tables.is_ms_shipped = 0 

Esta consulta retorna resultados como abaixo, que mostra a lista de índices, suas colunas e uso. Muito útil para determinar qual índice tem melhor desempenho que outros:

lista de índices, colunas e uso

Como seu perfil informa que você está usando o .NET, você pode usar o Server Managed Objects (SMO) programaticamente … caso contrário, qualquer uma das respostas acima é fantástica.

A solução acima é elegante, mas de acordo com o MS, o INDEXKEY_PROPERTY está sendo reprovado. Consulte: http://msdn.microsoft.com/pt-br/library/ms186773.aspx

No Oracle

 select CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME,CONNECYBY.COLUMN_NAME from ( select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,COLUMN_POSITION,trim(',' from sys_connect_by_path(COLUMN_NAME,',')) COLUMN_NAME from DBA_IND_COLUMNS start with COLUMN_POSITION = 1 connect by TABLE_OWNER = prior TABLE_OWNER and TABLE_NAME = prior TABLE_NAME and INDEX_NAME = prior INDEX_NAME and COLUMN_POSITION = prior COLUMN_POSITION + 1) CONNECYBY join ( select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,max(COLUMN_POSITION) COLUMN_POSITION from DBA_IND_COLUMNS group by TABLE_OWNER,TABLE_NAME,INDEX_NAME) MAX_CONNECYBY on ( CONNECYBY.SCHEMA_NAME = MAX_CONNECYBY.SCHEMA_NAME and CONNECYBY.TABLE_NAME = MAX_CONNECYBY.TABLE_NAME and CONNECYBY.INDEX_NAME = MAX_CONNECYBY.INDEX_NAME and CONNECYBY.COLUMN_POSITION = MAX_CONNECYBY.COLUMN_POSITION) order by CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME 

No SQL Server com

 CONNECTBY(SCHEMA_NAME,TABLE_NAME,INDEX_NAME,INDEX_COLUMN_ID,COLUMN_NAME) as ( select SCHEMAS.NAME SCHEMA_NAME , TABLES.NAME TABLE_NAME , INDEXES.NAME INDEX_NAME , INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID , cast(COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME from SYS.INDEXES join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID) join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID) join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID) join SYS.COLUMNS on ( INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID) where INDEX_COLUMNS.INDEX_COLUMN_ID = 1 union all select SCHEMAS.NAME SCHEMA_NAME , TABLES.NAME TABLE_NAME , INDEXES.NAME INDEX_NAME , INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID , cast(PRIOR.COLUMN_NAME + ',' + COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME from SYS.INDEXES join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID) join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID) join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID) join SYS.COLUMNS on ( INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID) join CONNECTBY as PRIOR on (SCHEMAS.NAME = PRIOR.SCHEMA_NAME and TABLES.NAME = PRIOR.TABLE_NAME and INDEXES.NAME = PRIOR.INDEX_NAME and INDEX_COLUMNS.INDEX_COLUMN_ID = PRIOR.INDEX_COLUMN_ID + 1)) select CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME,CONNECTBY.COLUMN_NAME from CONNECTBY join ( select SCHEMA_NAME , TABLE_NAME , INDEX_NAME , MAX(INDEX_COLUMN_ID) INDEX_COLUMN_ID from CONNECTBY group by SCHEMA_NAME,TABLE_NAME,INDEX_NAME) MAX_CONNECTBY on (CONNECTBY.SCHEMA_NAME = MAX_CONNECTBY.SCHEMA_NAME and CONNECTBY.TABLE_NAME = MAX_CONNECTBY.TABLE_NAME and CONNECTBY.INDEX_NAME = MAX_CONNECTBY.INDEX_NAME and CONNECTBY.INDEX_COLUMN_ID = MAX_CONNECTBY.INDEX_COLUMN_ID) order by CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME 

Basta observar que, se você for usar qualquer uma das consultas de trabalho acima para fazer o script de seus índices, será necessário incorporar a coluna filter_definition da tabela sys.indexes em suas consultas para obter a definição de filtro de índices não clusterizados no SQL 2008+

SOU

Aqui está a melhor maneira de fazer isso:

 SELECT sys.tables.object_id, sys.tables.name as table_name, sys.columns.name as column_name, sys.indexes.name as index_name, sys.indexes.is_unique, sys.indexes.is_primary_key FROM sys.tables, sys.indexes, sys.index_columns, sys.columns WHERE (sys.tables.object_id = sys.indexes.object_id AND sys.tables.object_id = sys.index_columns.object_id AND sys.tables.object_id = sys.columns.object_id AND sys.indexes.index_id = sys.index_columns.index_id AND sys.index_columns.column_id = sys.columns.column_id) AND sys.tables.name = 'your_table_name' 

Eu prefiro usar associações implícitas, pois é muito mais fácil para eu entender. Você pode remover a referência object_id, pois talvez não seja necessária.

Felicidades.

Primeiro, observe que todas as consultas acima podem perder ou erroneamente incorporar as colunas INCLUDE dos índices. Também está faltando em alguns a ordem correta e / ou a opção ASC / DESC das colunas.

Modificado a consulta acima por jona. Como um aparte, em muitos dos bancos de dados que eu uso, eu instalo minha própria function agregada CLR CONCATENATE, então o código abaixo depende de algo assim estar presente. As instruções SQL acima se reduzem a uma manutenção muito mais fácil:

 SELECT s.[name] AS [schema_name] , t.[name] AS [table_name] , i.[name] AS [index_name] , dbo.Concatenate(CASE WHEN ic.[key_ordinal] > 0 AND ic.[is_descending_key] = 1 THEN c.[name] + ' DESC' WHEN key_ordinal > 0 THEN c.[name] ELSE NULL END,',',1) AS [columns] , dbo.Concatenate(CASE WHEN ic.[is_included_column] = 1 THEN c.[name] ELSE NULL END,',',1) AS [includes] FROM sys.tables t INNER JOIN sys.schemas s ON t.[schema_id] = s.[schema_id] INNER JOIN sys.indexes i ON i.[object_id] = t.[object_id] INNER JOIN sys.index_columns ic ON ic.[object_id] = t.[object_id] AND ic.index_id = i.index_id INNER JOIN sys.columns c ON c.[object_id] = t.[object_id] AND ic.column_id = c.column_id GROUP BY s.[name] , t.[name] , i.[name] ORDER BY s.[name] , t.[name] , i.[name] 

Há muitos agregados de concatenação por aí, se o seu ambiente permitir que funções baseadas em CLR sejam adicionadas a ele.

Para colunas exclusivas por índice:

 select s.name, t.name, i.name, i.index_id,c.name,c.column_id from sys.schemas s inner join sys.tables t on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id where i.object_id = object_id('previous.account_1') order by index_id,column_id 

A consulta abaixo inclui todas as informações pertinentes para os índices definidos pelo usuário (sem índices para restrições exclusivas e chaves primárias) com todas as colunas:

 SELECT I.name as IndexName, CASE WHEN I.is_unique = 1 THEN 'Yes' ELSE 'No' END as 'Unique', I.type_desc COLLATE DATABASE_DEFAULT as Index_Type, '[' + SCHEMA_NAME(T.schema_id) + ']' as 'Schema', '[' + T.name + ']' as TableName, STUFF((SELECT ', [' + C.name + CASE WHEN IC.is_descending_key = 0 THEN '] ASC' ELSE '] DESC' END FROM sys.index_columns IC INNER JOIN sys.columns C ON IC.object_id = C.object_id AND IC.column_id = C.column_id WHERE IC.is_included_column = 0 AND IC.object_id = I.object_id AND IC.index_id = I.Index_id FOR XML PATH('')), 1, 2, '') as Key_Columns, Included_Columns, I.filter_definition, CASE WHEN I.is_padded = 1 THEN 'ON' ELSE 'OFF' END as PAD_INDEX, CASE WHEN ST.no_recompute = 0 THEN 'OFF' ELSE 'ON' END as [Statistics_Norecompute], CONVERT(VARCHAR(5), CASE WHEN I.fill_factor = 0 THEN 100 ELSE I.fill_factor END) as [Fillfactor], CASE WHEN I.ignore_dup_key = 1 THEN 'ON' ELSE 'OFF' END as [Ignore_Dup_Key], CASE WHEN I.allow_row_locks = 1 THEN 'ON' ELSE 'OFF' END as [Allow_Row_Locks], CASE WHEN I.allow_page_locks = 1 THEN 'ON' ELSE 'OFF' END [Allow_Page_Locks] FROM sys.indexes I INNER JOIN sys.tables T ON T.object_id = I.object_id INNER JOIN sys.stats ST ON ST.object_id = I.object_id AND ST.stats_id = I.index_id INNER JOIN sys.data_spaces DS ON I.data_space_id = DS.data_space_id INNER JOIN sys.filegroups FG ON I.data_space_id = FG.data_space_id LEFT OUTER JOIN (SELECT * FROM (SELECT IC2.object_id, IC2.index_id, STUFF((SELECT ', ' + C.name FROM sys.index_columns IC1 INNER JOIN sys.columns C ON C.object_id = IC1.object_id AND C.column_id = IC1.column_id AND IC1.is_included_column = 1 WHERE IC1.object_id = IC2.object_id AND IC1.index_id = IC2.index_id GROUP BY IC1.object_id, C.name, index_id FOR XML PATH('') ), 1, 2, '') as Included_Columns FROM sys.index_columns IC2 GROUP BY IC2.object_id, IC2.index_id) tmp1 WHERE Included_Columns IS NOT NULL ) tmp2 ON tmp2.object_id = I.object_id AND tmp2.index_id = I.index_id WHERE I.is_primary_key = 0 AND I.is_unique_constraint = 0; 

As an added bonus, the below query is formatted to write out the create index and drop index scripts:

 SELECT I.name as IndexName, -- Uncommnent line below to include checking for index exists as part of the script --'IF NOT EXISTS (SELECT name FROM sysindexes WHERE name = '''+ I.name +''') ' + 'CREATE ' + CASE WHEN I.is_unique = 1 THEN ' UNIQUE ' ELSE '' END + I.type_desc COLLATE DATABASE_DEFAULT + ' INDEX [' + I.name + '] ON [' + SCHEMA_NAME(T.schema_id) + '].[' + T.name + '] (' + STUFF( (SELECT ', [' + C.name + CASE WHEN IC.is_descending_key = 0 THEN '] ASC' ELSE '] DESC' END FROM sys.index_columns IC INNER JOIN sys.columns C ON IC.object_id = C.object_id AND IC.column_id = C.column_id WHERE IC.is_included_column = 0 AND IC.object_id = I.object_id AND IC.index_id = I.Index_id FOR XML PATH('')), 1, 2, '') + ') ' + ISNULL(' INCLUDE (' + IncludedColumns + ') ', '') + ISNULL(' WHERE ' + I.filter_definition, '') + 'WITH (PAD_INDEX = ' + CASE WHEN I.is_padded = 1 THEN 'ON' ELSE 'OFF' END + ', STATISTICS_NORECOMPUTE = ' + CASE WHEN ST.no_recompute = 0 THEN 'OFF' ELSE 'ON' END + ', SORT_IN_TEMPDB = OFF' + ', FILLFACTOR = ' + CONVERT(VARCHAR(5), CASE WHEN I.fill_factor = 0 THEN 100 ELSE I.fill_factor END) + ', IGNORE_DUP_KEY = ' + CASE WHEN I.ignore_dup_key = 1 THEN 'ON' ELSE 'OFF' END + ', ONLINE = OFF' + ', ALLOW_ROW_LOCKS = ' + CASE WHEN I.allow_row_locks = 1 THEN 'ON' ELSE 'OFF' END + ', ALLOW_PAGE_LOCKS = ' + CASE WHEN I.allow_page_locks = 1 THEN 'ON' ELSE 'OFF' END + ') ON [' + DS.name + '];' + CHAR(13) + CHAR(10) + 'GO' as [CreateIndex], 'DROP INDEX ['+ I.name +'] ON ['+ SCHEMA_NAME(T.schema_id) +'].['+ T.name +'];' + CHAR(13) + CHAR(10) + 'GO' AS [DropIndex] FROM sys.indexes I INNER JOIN sys.tables T ON T.object_id = I.object_id INNER JOIN sys.stats ST ON ST.object_id = I.object_id AND ST.stats_id = I.index_id INNER JOIN sys.data_spaces DS ON I.data_space_id = DS.data_space_id INNER JOIN sys.filegroups FG ON I.data_space_id = FG.data_space_id LEFT OUTER JOIN (SELECT * FROM (SELECT IC2.object_id, IC2.index_id, STUFF((SELECT ', ' + C.name FROM sys.index_columns IC1 INNER JOIN sys.columns C ON C.object_id = IC1.object_id AND C.column_id = IC1.column_id AND IC1.is_included_column = 1 WHERE IC1.object_id = IC2.object_id AND IC1.index_id = IC2.index_id GROUP BY IC1.object_id, C.name, index_id FOR XML PATH('') ), 1, 2, '') as IncludedColumns FROM sys.index_columns IC2 GROUP BY IC2.object_id, IC2.index_id) tmp1 WHERE IncludedColumns IS NOT NULL ) tmp2 ON tmp2.object_id = I.object_id AND tmp2.index_id = I.index_id WHERE I.is_primary_key = 0 AND I.is_unique_constraint = 0 

Using SQL Server 2016, this gives a complete list of all indexes, with an included dump of each table so you can see how the tables relate. It also shows columns included in covering indexes:

 select t.name TableName, i.name IdxName, c.name ColName , ic.index_column_id ColPosition , i.type_desc Type , case when i.is_primary_key = 1 then 'Yes' else '' end [Primary?] , case when i.is_unique = 1 then 'Yes' else '' end [Unique?] , case when ic.is_included_column = 0 then '' else 'Yes - Included' end [CoveredColumn?] , 'indexes >>>>' [*indexes*], i.*, 'index_columns >>>>' [*index_columns*] , ic.*, 'tables >>>>' [*tables*] , t.*, 'columns >>>>' [*columns*], c.* from sys.index_columns ic join sys.tables t on t.object_id = ic.object_id join sys.columns c on c.object_id = t.object_id and c.column_id = ic.column_id join sys.indexes i on i.object_id = t.object_id and i.index_id = ic.index_id order by TableName, IdxName, ColPosition 

I have used the following query when I had this requirement…

 SELECT TableName = t.name, ColumnId = col.column_id, ColumnName = col.name, DataType = ty.name, MaxSize = ty.max_length, IsNullable = CASE WHEN (col.is_nullable = 1) THEN 'Y' END, IsIdentity = CASE WHEN (col.is_identity = 1) THEN 'Y' END, IsPrimaryKey = CASE WHEN (ic.column_id = col.column_id) THEN 'Y' END, IsForeignKey = CASE WHEN (fkc.parent_column_id = col.column_id) THEN 'Y' END, IsDefault = CASE WHEN (dc.parent_column_id = col.column_id) THEN 'Y' END FROM sys.tables t INNER JOIN sys.columns col ON t.object_id = col.object_id LEFT JOIN sys.indexes ind ON t.object_id = ind.object_id LEFT JOIN sys.index_columns ic ON ic.index_id=ind.index_id AND ic.object_id = col.object_id and ic.column_id = col.column_id LEFT JOIN sys.foreign_key_columns fkc ON fkc.parent_object_id = col.object_id AND fkc.parent_column_id=col.column_id LEFT JOIN sys.default_constraints dc ON dc.parent_object_id = col.object_id AND dc.parent_column_id=col.column_id LEFT JOIN sys.types ty on ty.user_type_id = col.user_type_id WHERE --t.name='' t.schema_id = 10 --SCHEMA ID AND ind.is_primary_key=1 ORDER BY t.name, ColumnId 
 sELECT TableName = t.name, IndexName = ind.name, --IndexId = ind.index_id, ColumnId = ic.index_column_id, ColumnName = col.name, key_ordinal, ind.type_desc --ind.*, --ic.*, --col.* FROM sys.indexes ind INNER JOIN sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id INNER JOIN sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id INNER JOIN sys.tables t ON ind.object_id = t.object_id WHERE ind.is_primary_key = 0 AND ind.is_unique = 0 AND ind.is_unique_constraint = 0 AND t.is_ms_shipped = 0 and t.name='CompanyReconciliation' --table name and key_ordinal>0 ORDER BY t.name, ind.name, ind.index_id, ic.index_column_id